Answer:
The distance is 9.8 m.
Explanation:
Given that,
Acceleration = -2.5 m/s²
Initial speed = 7 m/s
We need to calculate the time
Using equation of motion
\(v = u+at\)
\(t=\dfrac{v-u}{a}\)
Where, v = final velocity
u = initial velocity
t = time
a = acceleration
Put the value into the formula
\(t =\dfrac{0-7}{-2.5}\)
\(t=2.8\ sec\)
We need to calculate the distance
Using equation of motion
\(s=ut+\dfrac{1}{2}at^2\)
\(s=7\times2.8-\dfrac{1}{2}\times2.5\times(2.8)^2\)
\(s=9.8\ m\)
Hence, The distance is 9.8 m.
