What is the volume of 3.70 mol of N2 gas at STP?
So when it says at STP, you are given the values of temperature and pressure.
T=273.15K
P=100kpa
R=8.314 (it's a constant)
n=3.70
V=?
Now use the formula PV=nRT and isolate for V
V=nRT/P
V=(3.70)(8.314)(273.15)/100
V=84.0L
The volume of 3.70 moles of N₂ gas at STP is 82.93 L
The volume of N₂ gas at STP can be obtained by using the ideal gas equation as illustrated below:
PV = nRT
1 × V = 3.7 × 0.0821 × 273
V = 82.93 L
Therefore, the volume of N₂ gas at STP is 82.93 L
Learn more about ideal gas equation:
https://brainly.com/question/4147359