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A spaceship moving with an initial velocity of 58.0 meters/second experiences a uniform acceleration and attains a final velocity of 153 meters/second. What distance has the spaceship covered after 12.0 seconds?


a.) 6.96 × 102 meters

b.) 1.27 × 103 meters

c.) 5.70 × 102 meters

d.) 1.26 × 102 meters

e.) 6.28 × 102 meters


this question is on CIVICS ... help !!!!

Verified Answer :

Livingsta

Given,

Initial velocity of spaceship (u) = 58 m/s
Final velocity of spaceship (v) = 153 m/s
Time taken (t) = 12 seconds

Since the spaceship moves with uniform acceleration, 

Distance (d) = 1/2 (u + v) t = 1/2 (58 + 153) 12 = 1266 m

1.27x10 to the 3rd power

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