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The function f(x) = x2 + 10x – 3 written in vertex form is f(x) = (x + 5)2 – 28. What are the coordinates of the vertex?

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The vertex of the quadratic equation is (-5, - 28). In vertex form, y = a(x - h)2 + k, (h, k) is the vertex of the equation.

calculista

Answer:

The coordinates of the vertex are \((-5,-28)\)

Step-by-step explanation:

we know that

The equation of a vertical parabola into vertex form is equal to

\(f(x)=a(x-h)^{2}+k\)

where

(h,k) is the vertex of the parabola

In this problem we have

\(f(x)=(x+5)^{2}-28\)

\(a=1. h=-5,k=-28\)

therefore

Is a vertical parabola open upward

The vertex is a minimum

The vertex is the point \((-5,-28)\)


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