The perimeter of a rectangle is given as:
\(P_{rect}=2w+2l\)
We know that
\(l=\frac{1}{3}*w{/tex]
as the length is one-third of the width. Now we can plug numbers in:
[tex]72=2w+\frac{2}{3}w = 72=\frac{8}{3}w\)
Now we can solve for width:
\(w=27\)
And if the length is one-third the width, we know that
\(27*\frac{1}{3} = 9
w=9\)
And \(A_{rect}=lw\)
So now we plug in numbers:
\(A_{rect}=27*9 = 243\)
