Answer : The amount of zinc metal react will be, 494.27 grams.
Solution : Given,
Volume of HCl solution = 5.4 L
Molarity of HCl solution = 2.8 M
Molar mass of zinc (Zn) = 65.38 g/mole
First we have to calculate the moles of HCl.
\(\text{Molarity of }HCl=\frac{\text{Moles of }HCl}{\text{Volume of solution}}\)
\(2.8M=\frac{\text{Moles of }HCl}{5.4L}\)
\(\text{Moles of }HCl=15.12moles\)
Now we have to calculate the moles of Zn.
The given balanced chemical reaction is,
\(Zn(s)+2HCl(aq)\rightarrow ZnCl_2(aq)+H_2(g)\)
From the balanced reaction, we conclude that
As, 2 moles of \(HCl\) react to with 1 mole of Zn
So, 15.12 moles of \(HCl\) react to with \(\frac{15.12}{2}=7.56\) moles of Zn
Now we have to calculate the mass of Zn.
\(\text{Mass of }Zn=\text{Moles of }Zn\times \text{Molar mass of }Zn\)
\(\text{Mass of }Zn=(7.56mole)\times (65.38g/mole)=494.27g\)
Therefore, the amount of zinc metal react will be, 494.27 grams.
