Verified Answer :

nobillionaireNobley

x^3 - x^2 + 2x - 2 = 0
for x = 1, (1)^3 - (1)^2 + 2(1) - 2 = 0
Thus x - 1 is a factor.

Dividing x^3 - x^2 + 2x - 2 by x - 1 gives x^2 + 2 which does not have real factors.
The factor of x^2 + 2 = (x - i√2)(x + i√2)

Therefore, The roots of x^3 - x^2 + 2x - 2 are x = 1, x = i√2 and x = -i√2

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