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What is the mass in grams of 13.06 mL of acetone

Acetone (fingernail-polish remover) has a density of 0.7857 g/cm3

Verified Answer :

MissPhiladelphia

to know the mass of the acetone we must multiply the volume of the acetone with its density. but since the volume is in ml units and the density is in g/cm3. we must convert it firstsince 1 ml = 1 cm3
so mass acetone = 13.06 mL (0.7857 g/ml)mass acetone = 10.848 g

Answer : The mass of acetone will be, 10.26 grams.

Explanation :

Density : It is defined as the mass contained per unit volume.

Formula used for density :

\(Density=\frac{Mass}{Volume}\)

Given :

Density of acetone = \(0.7857g/cm^3=0.7857g/mL\)

Volume = 13.06 mL

Now put all the given values in the above formula, we get the mass of acetone.

\(0.7857g/mL=\frac{Mass}{13.06mL}\)

\(Mass=10.26g\)

Therefore, the mass of acetone will be, 10.26 grams.

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