solving system of equations by substitution
y=3x-10 and 3x+2y=16y=3x-10subsitute 3x-10 for y in other equation3x+2y=163x+2(3x-10)=16distribute3x+6x-20=169x-20=16add 20 both sides9x=36divide both sides by 9x=4sub backy=3x-10y=3(4)-10y=12-10y=2x=4y=2(4,2) is soluiton