Verified Answer :

Sansacrasial

\(\sqrt{x+6} =x-6\)
\(x+6=(x-6)^2\)
\(x+6=x^2-12x+36\)
Subtract \(x^2-12x+36\) from both sides:
\(x+6-(x^2-12x+36)=x^2-12x+36-(x^2-12x+36)\)
\(-x^2+13x-30=0\)
\((-x+3)(x-10)=0\)
\(-x+3=0\) or \(x-10=0\)
Plug 3 into the equation:
\(\sqrt{3+6}=3-6\)
\(3 eq -3\)
Plug 10 into your equation:
\(\sqrt{10+6} =10-6\)
\(4=4\)
So, your answer is: 
\(10\)

Good luck with your studies, I hope this helps!~

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