Let f(x) = 2x – 1, g(x) = 3x, and h(x) = x2 + 1. Compute the following.
For number 3, We can do the same thing as we did for number 1. First of all, we start from f(- 5), which means we have to replace x with - 5. So f(- 5) = 2 - 5 - 1 = - 10 - 1 = - 11. So now we are looking for g(- 11), and we also substitute x for - 11 here, so g(- 11) = 3 -11 = - 33. So our answer is - 33.
About question 2, I don't know what that o is for.
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