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Which represents the balanced equation for the beta minus emission of phosphorus-32?

A32/15P ---> 28/13 Al + 2/4 He
B32/15P ---> 32/14 Si + 0/-1 e
C32/15P ---> 32/16 S + 0/-1 e
D32/15P ---> 32/14 Si + 0/+1 e

Verified Answer :

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Answer : Option C) \(P^{32}_{15} ---> S^{32}_{16} +e^ {0}_{-1}\)

Explanation : The balanced equation for the beta minus decay for emission of Phosphorus-32 is \(P^{32}_{15} ---> S^{32}_{16} +e^ {0}_{-1}\)

Where, it is clearly seen that in the beta minus emission a neutron decays into a proton, an electron, and an anti-neutrino.

So, in the phosphorus-32 beta minus decay the product is sulfur-32 along with an electron created from the anti-neutrino.

Therefore, option C is the correct option.

Answer: The correct option is C.

Explanation: Beta minus ( \(\beta ^-\) ) decay is the decay in which a neutron is converted into proton and releases beta particle or generally known as electron.

There is an increase in the Atomic number because one protons is being formed.

In the case of beta-minus decay of phosphorous, the P-nucleus gets changed to Sulfur nucleus. The balanced Chemical equation for this process is:

\(^{32}_{15}\textrm{P}\rightarrow ^{32}_{16}\textrm{S}+^0_{-1}\beta\)

Hence, the correct option is C.

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