The vertex angle of an isosceles triangle measures 42°. A base angle in the triangle has a measure given by (2x + 3)°. What is the value of x? What is the measure of each base angle?
the 2 base angles are equal so the measure of 1 base angle = (180 - 42) / 2
= 69 degrees
2x + 3 = 69
2x = 66
x = 33
each base angle measures 69 degrees
The base angles of an isosceles triangle are equal.
The value of x is 33, and the measure of each base angle is 69.
The given parameter are:
\(\mathbf{Vertex = 42}\)
\(\mathbf{Base = 2x + 3}\)
So, we have:
\(\mathbf{2x + 3 + 2x +3 + 42 = 180}\)
Collect like terms
\(\mathbf{2x + 2x = 180 - 42 - 3 - 3}\)
\(\mathbf{4x = 132}\)
Divide both sides by 4
\(\mathbf{x = 33}\)
Recall that:
\(\mathbf{Base = 2x + 3}\)
So, we have:
\(\mathbf{Base = 2(33) + 3}\)
\(\mathbf{Base = 69}\)
Hence, the value of x is 33, and the measure of each base angle is 69.
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