Arrange the following interest rates in ascending order: 3.4%, 3.039%,3 3/16%,3.499%,3 1/2%
Answer:
3.039% < \(3\frac{3}{16}\)% < 3.4% < 3.499% < \(3\frac{1}{2}\)%
Step-by-step explanation:
We have to arrange the following interest rates in ascending order.
3.4%, 3.039%, \(3\frac{3}{16}\)%, 3.499%, \(3\frac{1}{2}\)%
First we have to convert these value in to fraction then into decimal value.
3.4% = \(\frac{3.4}{100}\) = 0.034
3.039% = \(\frac{3.039}{100}\) = 0.03039
\(3\frac{3}{16}\)% = \(\frac{51}{16}\)% = \(\frac{3.1875}{100}\) = 0.031875
3.499% = \(\frac{3.499}{100}\) = 0.03499
\(3\frac{1}{2}\)% = \(\frac{7}{2}\)% = \(\frac{3.5}{100}\) = 0.035
Now we will arrange these decimal numbers in to ascending order.
0.03039 < 0.031875 < 0.034 < 0.03499 < 0.035
Therefore the interest rates in ascending order would be
3.039% < \(3\frac{3}{16}\)% < 3.4% < 3.499% < \(3\frac{1}{2}\)%