What is the equation of a circle whose center is at the origin and whose radius is 16? x2 + y2 = 4 x2 + y2 = 16 x2 + y2 = 256
Answer:
3. \(x^2+y^2=256\)
Step-by-step explanation:
We are asked to find the equation of circle, whose center is at the origin (0,0) and whose radius is 16.
We know that standard form of a circle is in form: \((x-h)^2+(y-k)^2=r^2\), where,
\((h,k)\) = Center of circle,
r = Radius of circle.
Upon substituting our given values in standard form of circle, we will get
\((x-0)^2+(y-0)^2=16^2\)
\(x^2+y^2=256\)
Therefore, 3rd option is the correct choice.