remember
(ab)/(cd)=(a/c)(b/d)
basically you can move around them
also
\(\frac{x^m}{x^n} =x^{m-n}\)
so
remember that the first number hast to be greater than 1 and less than 10
\(\frac{8.82*10^5}{9*10^2}= ( \frac{8.82}{9} )( \frac{10^5}{10^2} )\)=
\((0.98)(10^3)=(0.98)(10^1)(10^2)=9.8*10^2\)
