A small class has

10

students,

6

of whom are girls and

4

of whom are boys. The teacher is going to choose two of the students at random. What is the probability that the first student chosen will be a boy and the second will be a girl? Write your answer as a fraction in simplest form.

For the selection of the first student, there are 10 students, 4 of which are boys. So there is a 4/10 = 2/5 probability that the first student chosen is a boy.

Now, for the second student. There are 9 students, of which 6 are girls. So there is a 6/9 = 2/3 probability that the second will be a girl when the first was a boy.

So

\(P = \frac{2}{5}*\frac{2}{3} = \frac{4}{15}\)

A small class has 10students, 6of whom are girls and 4of whom are boys. The teacher is going to choose two of the students at random. What is the probability that the first student chosen will be a boy and the second will be a girl? Write your answer as a fraction in simplest form.

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Related Questions

A small class has

10

students,

6

of whom are girls and

4

of whom are boys. The teacher is going to choose two of the students at random. What is the probability that the first student chosen will be a boy and the second will be a girl? Write your answer as a fraction in simplest form.