Ammary2j
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when 10x^3+mx^2-x+10 is divided by 5x-3, the quotient is 2x^2 +nx-2 and the remainder is 4. Find the values of m and n.

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PsychrolutesMarcidus

\(\frac{10x ^{3} +mx^2- x +10 }{5x -3} = 2x^2 +nx -2 +4\)
=\(\frac{10x ^{3} +mx^2- x +10 }{5x -3} = 2x^2 +nx +2\)
=\(10x ^{3} +mx^2- x +10= (2x^2 +nx +2)(5x -3)\)
=\(10x ^{3} +mx^2- x +10=10x^3 + 5nx^2 +10x -6x^2 -3nx -6\)
=\(mx^2- x +10= + 5nx^2 +10x -6x^2 -3nx -6\)
=\(mx^2- x +10=(5n-6)x^2 +(10 -3n)x -6\)
=\((5n-6-m)x^2 +(10 -3n+1)x -16\)
= \((5n-6-m)x^2 +(11-3n)x -16\)

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