Data:
F (force) = ? (Newton)
k (Constant spring force) = 50 N/m
x (Spring deformation) = 15 cm → 0.15 m
Formula:
\(F = k*x\)
Solving:
\(F = k*x\)
\(F = 50*0.15\)
\(\boxed{\boxed{F = 7.5\:N}}\end{array}}\qquad\quad\checkmark\)
Data:
E (energy) = ? (joule)
k (Constant spring force) = 50 N/m
x (Spring deformation) = 15 cm → 0.15 m
Formula:
\(E = \frac{k*x^2}{2}\)
Solving:(Energy associated with this stretching)
\(E = \frac{k*x^2}{2}\)
\(E = \frac{50*0.15^2}{2}\)
\(E = \frac{50*0.0225}{2}\)
\(E = \frac{1.125}{2}\)
\(\boxed{\boxed{E = 0.5625\:J}}\end{array}}\qquad\quad\checkmark\)
