Answer:
\(\frac{2x^{-4}}{3xy}=\frac{2}{3x^5y}\)
Step-by-step explanation:
Simplify: 2x^-4/3xy
\(\frac{2x^{-4}}{3xy}\)
To simplify it we use exponential property
\(\frac{a^m}{a^n} =a^{m-n}\)
we can simplify x
\(\frac{x^{-4}}{x^1} =x^{-4-1}=x^{-5}\)
\(\frac{2x^{-4}}{3xy}=\frac{2x^{-5}}{3y}\)
Now we take reciprocal to remove negative. we move x^-5 to the denominator
\(\frac{2x^{-4}}{3xy}=\frac{2}{3x^5y}\)
