Answer:
Option B
Step-by-step explanation:
In the figure, attached, given line passes through two points ( 3, 1 ) and ( 0, 1 ).
So slope of the line will be = \(\frac{(y-y')}{(x-x')}\)
= \(\frac{(1+1)}{(3-0)}\)
= \(\frac{2}{3}\)
Now a line which is parallel to this line will have same slope as ( \(\frac{2}{3}\) ) and equation will be y = \(\frac{2}{3}\)x + c
Now it is given that this line passes through ( -3, 0 )
[ x-intercept given as (-3)]
We plug in the values in the equation to get the value of c
0 = \(\frac{2}{3}\) ( -3) + 6
0 = -2 + c ⇒ c = 2
Therefore, equation will be y = \(\frac{2}{3}\)x + 2
Option B is the answer.
