Let
\(x=3\frac{1}{2} \\ \\ y=-1\frac{1}{2}\)
Find the sum of the mixed numbers x and y
\((x+y)=3\frac{1}{2}+(-1\frac{1}{2})\\ \\(x+y)=2\)
therefore
the answer is
Yes, the sum of two mixed numbers be equal to \(2\), only if you include a negative mixed number