remember
\((abc)^x=(a^x)(b^x)(c^x)\)
and
\((x^m)(x^n)=x^{m+n}\)
and
\((x^m)^n=x^{mn}\)
and
\(x^{-m}= \frac{1}{x^m}\)
so
\((5x^7y^3z^{-1})^2(2xy^{-5})^3(2y^{-3}z^2)^3\)=
\((5^2)((x^7)^2)((y^3)^2)((z^{-1})^2)(2^3)(x^3)((y^{-5})^3)(2^3)((y^{-3})^3)((z^2)^3)\)=
\((25)(x^{14})(y^6)(z^{-2})(8)(x^3)(y^{-15})(8)(y^{-9})(z^6)\)=
\(1600x^{17}y^{-18}z^4\)=
\(\frac{1600x^{17}z^4}{y^{18}}\)
