Verified Answer :

abates950

The x-intercepts are the x-coordinates of the points where the graph crosses the x-axis. Thus, for these points the y-coordinate is zero. Thus, in the equation set y = 0 and solve for x. Similarly to find the y-intercepts, set x = 0 in the equation and solve for x.

Hope that helped! :)

apologiabiology

in form
\((x-h)^2+(y-k)^2=r^2\)
the circle has a center of (h,k) and radius of r

when a circle is on the x axis, y=0
so when k=0

so if you have anything like this
\((x-h)^2+(y-0)^2=r^2\) or more simply
\((x-h)^2+y^2=r^2\)

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