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Answered

Two equations are given below:

a - 3b = 16

a = b - 2

What is the solution to the set of problems in the form (a, b)?

A(-2, -6)
B(-7, -9)
C(-11, -9)
D(-12, -10)

Verified Answer :

AISstudent

You can solve this question by equating the two linear systems (by "substitution" or "elimination")

By substitution
-Take Equation 2 and substitute it in Equation 1
you will have (b-2) - 3b= 16 => -2b=18 => b=-9
-Then, take b=-9 and substitute it in one of the equations( it doesn't really matter )
For eg substituting in equation 2 yields a=-11

Final ans: C where (a,b) is (-11,-9)

The solution of the given set in the form (a, b) is (-11, -9).

What is system of equations?

The system of equations can be solved by using substitution method

The given equations are

\(a-3b=16\\a=b-2\)

On substituting the value of a in equation \(1\) we get,

⇒\((b-2)-3b=16\)

⇒\(-2b=16+2\)

⇒\(-2b=18\)

⇒\(b=-9\)

On substituting the value of \(b\) in \(a\),

\(a=-9-2\\\)

⇒\(a=-11\)

Hence, option (C) is correct.

Learn more about system of equations here

https://brainly.com/question/24496050

#SPJ2

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