Alright. So for:
a) 4(x+7)+3(x+5) Here we need to distribute the
number outside of the parenthesis to the terms inside. So after
distributing, we get 4x+28+3x+15. Then simplify this equation to 7x+43.
b)
3(2a+4b)+9(3a-2b) Same here. We distribute the number outside of the
parenthesis to the terms inside. After distributing, we get
6a+12b+27a-18b. Then simplify to get 33a-6b.
c) 2(3u-5)-3(2u+1) As
expected, same here. We distribute the number outside of the
parenthesis. But here, we have a negative. Remember to distribute that
as well. So we get 6u-10-6u-3. Then we simplify and get -13.
d)
b(-5v-4)-2b(v+4) -_- Getting a bit boring... We distribute the variable
from outside the parenthesis into the terms in the parenthesis. We get
-5bv-4b-2bv-8b. Then simplify to get -3bv-12b.
**If you don't understand distributing, just let me know!
