Interesting question! Let's first break this up:
\(\frac{4!8!}{2!7!}= \frac{1x2x3x4x1x2x3x4x5x6x7x8}{1x2x1x2x3x4x5x6x7}\)
We can now simplify this by crossing out numbers that appear in both denominator and numerator. This becomes
\(\frac{3x4}{1}\)
Therefore, the answer is 12
