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Sean’s age and Helen’s age are in the ratio of 3:5. Two years ago, Helen was twice as old as Sean was then. Find their present ages.

Verified Answer :

Lets Sean's age be x
Helen's age by y
x/y=3/5
x=3/5y

Second equation
2(x-2)=y-2

on solving u get Helen as 10 and Sean as 6

aksnkj

The present age of Sean is 6 years and the present age of Helen is 10 years.

Given,

The ratio of Sean's age and Helen's age is 3:5.

Let the present age of Sean be \(3x\) years and the present age of Helen be \(5x\) years.

So two years ago,

Helen's age was \((5x-2)\) years and Sean's age was \((3x-2)\) years.

According to the question, Two years ago,

Helen was twice as old as Sean was then.

How to write linear equations?

So in equation form, we get

\((5x-2)=2(3x-2)\)

\(5x-2=6x-4\)

\(x=2\).

So, the present age of Sean will be \(3\times2 =6\) years.

The present age of Helen will be \(5\times2=10\) years.

For more details about linear equations, follow the link:

https://brainly.com/question/22048320

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