Verified Answer :

miner3mj

2(x-2)^2 +3. You ignore the 7 and complete the square for 2x^2 -8 and then subtract what you add from the 7

MindTrickery

Answer:

3

Step-by-step explanation:

The problem is to complete the square on the quadratic expression 2x^2 - 8x + 7. First, we write

                                    2x^2 - 8x + 7 = 2(x^2 - 4x) + 7

We want a square that includes the terms x^2 and -4x. This desired square is


(x - 2)^2 = x^2 - 4x + 4

Hence,


                                    2(x^2 - 4x) + 7 &= 2[(x^2 - 4x + 4) - 4] + 7  

                                        = 2[(x - 2)^2 - 4] + 7  

                                        = 2(x - 2)^2 - 8 + 7  

                                        = 2(x - 2)^2 - 1.


Therefore, a = 2, h = 2, and k = -1, and a+h+k = 3