Answer:
\(\frac{4}{10} =\frac{3.2}{8}\)
Step-by-step explanation:
Given : AD=4
DB=6
AE=3.2
EC=4.8
AB=10
AC=8
Solution :
Theorem :A transversal that is parallel to one of the sides in a triangle divides the other two sides proportionally.
So,
\(\frac{AD}{AB} =\frac{AE}{AC}\)
\(\frac{4}{10} =\frac{3.2}{8}\)
\(\frac{4}{10} =\frac{32}{80}\)
Reduce the fraction both sides by dividing both the fractions with common factor respectively.
\(\frac{2}{5} =\frac{2}{5}\)
Thus ans in boxes will be \(\frac{4}{10} =\frac{3.2}{8}\)
This verify that BC ∥ DE.
