Verified Answer :


Data:
\(tg\^A = ?\)
\(Opposite (side) = 12\)
\(Adjacent (side) = 9\)

Solving:
The tangent of angle  is the ratio of the opposite (BC) and adjacent (AC):
\(tg\^{A} = \frac{opposite}{adjacent}\)
\(tg\^A = \frac{12}{9}\)
\(\boxed{\boxed{tg\^A \approx1.3}}\end{array}}\qquad\quad\checkmark\)


Applying the trigonometry ratio, \(tan(\theta) = \frac{Opp}{Adj}\), the value of tan A is: 1.33

Recall:

  • To solve a right triangle, the trigonometry ratios, SOH CAH TOA, is usually applied.

Thus, to find tan A, we would apply TOA.

  • This is given as:

\(tan(\theta) = \frac{Opp}{Adj}\)

Where,

Reference angle \((\theta) = A\)

Opp. = 12

Adj. = 9

  • Substitute

\(tan(A) = \frac{12}{9} \\\\\mathbf{tan(A) = 1.33}\)

Therefore, applying the trigonometry ratio, \(tan(\theta) = \frac{Opp}{Adj}\), the value of tan A is: 1.33

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