10-02-2017
Chemistry

Answered

how much water is present in 83.0 g of Li3PO4 * 12H2O?

Verified Answer :

11-02-2017

Try dividing the 83.0 g by the molar mass of Li3PO4* 12H2O and then multiply that result by a number of H2O moles (12). You should get 3.0027 mol.

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