what is the atomic mass of an element if 4.00 grams of it contains 2.98x10^22 atoms
Atomic mass is the same as the grams per mole. 2.98x10²² is 0.0495 mol (2.98e22 ÷ 6.02e23). If we have 4 g/0.0495 mol, that's 80.81 g/mol, so the atomic mass is 80.81 amu. Make sense?
Answer: The molar mass of the element is 80.8 g/mol
Explanation:
We are given:
Number of atoms = \(2.98\times 10^{22}\)
According to mole concept:
\(6.022\times 10^{23}\) number of atoms are contained in 1 mole of an element
So, \(2.98\times 10^{22}\) number of atoms will be contained in \(\frac{1}{6.022\times 10^{23}}\times 2.98\times 10^{22}=0.0495mol\) of an element
To calculate the molar mass for given number of moles, we use the equation:
\(\text{Number of moles}=\frac{\text{Given mass}}{\text{Molar mass}}\)
Given mass of element = 4.00 g
Moles of an element = 0.0495 moles
Putting values in above equation, we get:
\(0.0495mol=\frac{4.00g}{\text{Molar mass of element}}\\\\\text{Molar mass of an element}=\frac{4.00g}{0.0495mol}=80.8g/mol\)
Hence, the molar mass of the element is 80.8 g/mol