Calculate the area of the figure below using the following information: Area of triangle ABC = 31.8 square units Area of triangle ACD = 39.2 square units Area of triangle AED = 35.5 square units Image of irregular pentagon with vertices points A, B, C, D, and E starting at upper left moving clockwise. Two dotted diagonal lines, one connecting vertices A and C, and the second connecting vertices A and D. The area of the Figure ABCDE is ______ square units. Answer for Blank 1:
Answer:
Area of irregular pentagon=106.5 square units.
Step-by-step explanation:
It is given that Area of triangle ABC = 31.8 square units,
Area of triangle ACD = 39.2 square units and
Area of triangle AED = 35.5 square units.
Thus, ABCDE makes an irregular pentagon, therefore
Area of irregular pentagon= Area of triangle ABC +Area of triangle ACD+Area of triangle AED
⇒Area of irregular pentagon=31.8+39.2+35.5
⇒Area of irregular pentagon=106.5 square units.
Thus, area of an irregular pentagon is 106.5 square units.