Verified Answer :

take the first 2 and take out -7x2. bringing it to (-7x2)(x-3)+(3x-9)
then take out 3 on the right side.
-7x^2 (x-3)+3 (x-3)
factors to (3-7x2)(x-3)

aksnkj

The resulting expression for factor of \(-7x^3 + 21x^2 + 3x- 9\) will be \((x-3)(3-7x^{2} )\).

Given expression,

\(-7x^3 + 21x^2 + 3x- 9\).

We have to factorize the above expression by grouping method.

How to perform factorization?

In grouping method of factorization we make group of two and take out common term.

Now from \(-7x^3 + 21x^2 + 3x- 9\).

Now taking out common term we get,

\(-7x^{2} (x-3)+3(x-3)\)

Taking \((x-3)\) common we get,

\((x-3)(-7x^{2} +3)\)

\((x-3)(3-7x^{2} )\).

Hence the correct option is C. \((x-3)(3-7x^{2} )\).

For more details about factorization, follow the link:

https://brainly.com/question/13114757