Two tuning forks are played at the same time. One has a frequency of 490 Hz and the other is 488 Hz. How many beats per second are heard?
When two tuning forks are played at the same time, the beats per second heard are 2 Hz.
It is the number of beats per second equal to the difference between frequencies of two interacting tones.
Given are the two interacting tones f2 = 490 Hz and f1 = 488 Hz.
Then, beat is equal to
B = f2 - f1
B = 490-488
B = 2 Hz
Thus, beats per second heard are 2 Hz.
Learn more about beat.
https://brainly.com/question/14705053
SPJ2