Answer:
Atomic mass of the element = 80.80 amu
Explanation:
Given:
Mass of element = 4.00 g
No. of atoms = \(2.98\times 10^{22}\)
\(mol = \frac{No.\ of\ atoms}{Avogadro's\ no.}\)
Avogadro's no. = tex]6.02\times 10^{23}[/tex]
\(mol = \frac{No.\ of\ atoms}{Avogadro's\ no.}\)
=\(\frac{2.98\times 10^{22}}{6.02\times 10^{23}} = 0.0495\ mol\)
Formula for moles in the terms of mass and atomic mass
\(mol = \frac{Mass\ in\ g}{Atomic\ mass} \\Atomic\ mass = \frac{Mass\ in\ g}{mol}\)
Atomic mass of the element = \(\frac{4.00}{0.0495} = 80.80\ amu\)
Atomic mass of the element = 80.80 amu
