Verified Answer :

f(3) =  3^3 - 149 + 619 - 84 =  0

so 3 is one zero

long division of the expression by (x - 3)  gives the quadratic x^2 -11x + 28 which = (x - 7)(x-4)   so the other zeros are 4 and 7.

3,4 and 7

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Answer:

The zeros of the function are

\(7,4,3\)

Step-by-step explanation:

we know that

The x-intercept  is the value of x when the value of the function is equal to zero.

The x-intercepts represents the zeros of the function

In this problem we have

\(f(x)=x^{3}-14x^{2} +61x-84\)

Using a graphing tool

see the attached figure

The zeros of the function are

\(7,4,3\)


View image calculista

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