Answer:
The perimeter of a figure be 27.85 ft .
Step-by-step explanation:
Formula
Perimeter of a square = 4a
Where a is the side of a square .
\(Perimeter\ of\ a\ circle = 2 \pi r\)
Where r is the radius of a circle .
As the figure given in the question is consist of the square and \(\frac{1}{4}th\) part of the circle .
As the length of the square side = 5 ft
Radius of the \(\frac{1}{4}th\) part of the circle = 5 ft
3.14 = π
Thus
\(Perimeter\ of\ figure = 4a + \frac{2\pi r}{4}\)
Putting values in the formula
\(Perimeter\ of\ figure = 4\times 5 + \frac{2\times 3.14\times 5}{4}\)
\(Perimeter\ of\ figure = 20 + \frac{31.4}{4}\)
\(Perimeter\ of\ figure = 20 +7.85\)
\(Perimeter\ of\ figure = 27.85 ft\)
Therefore the perimeter of a figure be 27.85 ft .
