When find the margin error for the mean of a normally distributed population from a sample what is the critical probability assuming a confidence level of 58%
To solve the problem we must know about the critical probability.
The critical probability when the confidence level of 58% is 0.79.
It is the essentially cut-off value that defines the region where the test statistic is unlikely to lie.
Given
The confidence level is 58%.
It is the measurement statisticians use to calculate the margin of error within a set of data and is expressed as
\(\rm Critical\ prebability\ (p*) = 1 - \dfrac{\alpha }{2}\)
where,
\(\rm \alpha = 1 - \dfrac{Confidence\ level}{100} \\\)
The confidence level is 58%.
Then
\(\rm \alpha = 1 - \dfrac{Confidence\ level}{100} \\\\\alpha = 1- \dfrac{58}{100} \\\\\alpha = 0.48\)
Then the critical probability will be
\(\rm Critical\ prebability\ (p*) = 1 - \dfrac{\alpha }{2} \\\\\rm Critical\ prebability\ (p*) = 1 - \dfrac{0.42}{2} \\\\\rm Critical\ prebability\ (p*) = 0.79\)
Thus, the critical probability is 0.79.
More about the critical probability link is given below.
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