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Choose the equation below whose axis of symmetry is x = 0.


y = x2 + 2x

y = x2 − 16x + 58

y = x2 + 2

y = x2 − 4x + 2

Verified Answer :

20031121

i think the answer would be y =x2+2

frika

The axis of symmetry of a parabola is a vertical line that divides the parabola into two congruent halves. The axis of symmetry always passes through the vertex of the parabola. The x-coordinate of the vertex of the parabola \(y=ax^2+bx+c\) can be found as

\(x_v=-\dfrac{b}{2a}.\)

The equation x=0 represents the y-axis, therefore, parabola should be symmetric about the y-axis. This means that parabola vertex is placed on the y-axis. If parabola vertex is placed on the y-axis, then \(x_v=0\) and

\(-\dfrac{b}{2a}=0\Rightarrow b=0.\)

Only third parabola has b=0, then

correct choice is C.


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