Answer:
\(\frac{1}{x^2y^{2}}\)
A is the correct option.
Step-by-step explanation:
The given expression is \(\frac{x^0y^{-3}}{x^2y^{-1}}\)
We know that any number raised with zero power equals 1. Thus, \(x^0=1\)
Hence, the expression becomes
\(\frac{y^{-3}}{x^2y^{-1}}\)
Now, apply the quotient rule, \(\frac{x^a}{x^b}=x^{a-b}\)
Using this rule, we have
\(\frac{1}{x^2y^{-1-(-3)}}\)
\(=\frac{1}{x^2y^{-1+3}}\)
\(=\frac{1}{x^2y^{2}}\)
Hence, the simplified expression is \(\frac{1}{x^2y^{2}}\)
A is the correct option.
