What is the volume of the item described? An ice cream cone with a cone of radius 2 cm and height of 9 cm with a hemisphere of ice cream on top of radius 2 cm. Select the exact answer in terms of π and the approximate answer rounded to the nearest whole number
Volume of hemisphere = 2πr³/3
Volume of cone = πr²h/3
Where r = 2 and h = 9
Volume = volume of hemisphere + volume of cone
Volume = 2π(2)³/3 + π(2)²(9)/3
Volume = 16π/3 + 36π/3
Volume = 52π/3
Answer:
The volume of item is \(\frac{52}{3}\pi\).
Step-by-step explanation:
The volume of cone
\(V_1=\frac{1}{3}\pi r^2h\)
Where r is radius of cone and h is the height of cone.
It is given that the radius of cone is 2 cm and the height of cone is 9 cm. So, the volume of cone is
\(V_1=\frac{1}{3}\pi (2)^2(9)=12\pi\)
The volume of hemisphere
\(V_2=\frac{2}{3}\pi r^3\)
Where r is radius of hemisphere.
It is given that the radius of hemisphere is 2 cm. So, the volume of hemisphere is
\(V_2=\frac{2}{3}\pi (2)^3=\frac{16}{3}\pi\)
The volume of ice cream is
\(V=V_1+V_2\)
\(V=12\pi+\frac{16}{3}\pi\)
\(V=\frac{36+16}{3}\pi\)
\(V=\frac{52}{3}\pi\)
Therefore the volume of item is \(\frac{52}{3}\pi\).