\(-\dfrac12x+3=-x+7\)
Add -3 to both sides:
\(-\dfrac12x+3-3=-x+7-3\)
\(-\dfrac12x=-x+4\)
Multiply both sides by -2:
\(-2\times\left(-\dfrac12\right)x=-2(-x+4)\)
\(x=-2(-x+4)\)
On the right hand side, distribute the -2:
\(x=2x-8\)
Add -2x to both sides:
\(x-2x=2x-2x-8\)
\(-x=-8\)
Divide by -1:
\(\dfrac{-x}{-1}=\dfrac{-8}{-1}\)
\(x=8\)
(and not \(x=-8\), unless the original equation wasn't correctly written/interpreted?)
