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  • 09-02-2017
  • Chemistry
Answered

As a person coughs the CO^2 exits the lungs at speed of about 30m/s, what is the KE?

Verified Answer :

remibell
remibell remibell
  • 09-02-2017

ke=(1/2)mv^2,   add up the mass of one carbon and two oxygen times it by velocity^2, divide by 2

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