Answer:
Acceleration, \(a=2.33\ m/s^2\)
Explanation:
It is given that,
Initial speed of Shelly, u = 0
After 6 seconds, she has reached a final velocity of 14 m/s, v = 14 m/s
We need to find the acceleration of Shelly. The formula to find the acceleration is given by :
\(a=\dfrac{v-u}{t}\)
\(a=\dfrac{14\ m/s-0}{6\ s}\)
\(a=2.33\ m/s^2\)
So, the acceleration of Shelly's is \(2.33\ m/s^2\). Hence, this is the required solution.
