Suppose you have a container divided by a membrane that is permeable to water but not to sugar. Side A has a 10% sugar solution. Side B has a 40% sugar solution. Both start out at 10 cm in height. Over time, the height of one side drops to 7 Cm and the height of the other side increases to 13 cm. Which side of the container is now at 7 cm? Explain.

the movement of water is from A to B !!

thus making equilibrium water in B must be more so that water is balanced in both !!

thus the water in B will be 13 and in A , 7 cm !!

so , the answer is A !! it has 7 cm of water !!

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batolisis batolisis · Answer 2 · 2021-10-03T17:36:23-04:00

The side of the container that is now 7 cm is ; side A while The side that will be 13 cm is side B

The situation depicted in this question is Osmosis. Osmosis is movement of water molecules from a lower concentrated solution to a highly concentrated solution through a semi-permeable membrane.

In this scenerio side A has a concentration of 10% sugar solution while side B has a 40% sugar concentration and they are divided by a permeable membrane ( semi-permeable ) because it allows only water molecules through.

Therefore water molecule will move from side A into side B through the membrane which will make the height of side B = 13 cm while side A will have a height of 7cm.

Hence we can conclude that The side of the container that is now 7 cm is ; side A and the side that will be 13 cm is side B

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