\(\frac{6e-3f}{4e-2f}\)
Now one thing that is important to know is that when you are factorizing, you have to look for what is common on both sides. Now first of all, in the numerator, 3 is common in both 6e and 3f, so we can bring it out to get \(3(2e-f)\). The same thing can be done for the denominator, giving us \(2(2e-f)\). Now in the fraction \(\frac{3(2e-f)}{2(2e-f)}\), \(\frac{2e-f}{2e-f} =1\)
So that means our answer is \(\frac{3}{2} *1=1 \frac{1}{2}\).
Please mark me as brainliest.
