If the first number is x-1, since the numbers are consecutive, the second number will be x, the third number will be x+1 and the fourth number will be x+2.
\((x-1)+(x)+(x+1)+(x+2)=354\)
\(4x+2=354\)
\(4x=354-2=352\)
Therefore,
\(x=88\)
So the second number is 88.
Please mark me as brainliest.
