Verified Answer :

Joshtray

If we add the last two equations we get
\(5x+3y=11\)
If we add the first and the last equations we get
\(3x+7y=17\)
Solving these two equations simultaneously you will get
x=1 and y=2
Putting these two values back into any of the equations given (i will use the third equation in this case), we get
\(1+2(4)+z=1+8+z=9+z=12\)
Therefore
\(z=12-9=3\)
So x=1, y=2 and z=3.
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